calculate the energy (kJ/mol) of 450 nm photon of visible radiation? h = 6.626x10^-34 J s, c = 3x10^8 m/s, mole = 6.02x10^23 photon, m = 10^9 nm a. 3.97x10^-28 kJ/mol b. 4.42x10^-19 kJ/mol c. 265.9 kJ/mol d. 239.3 kJ/mol
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Plugging in the values given, we get: E = (6.626x10^-34 J s) x (3x10^8 m/s) / (450x10^-9 m) E = 4.42x10^-19 J Show more…
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