00:01
Hi, the conversion of 100 g of ice at minus 40 degree celsius to water at 0 degree celsius will take place in two step.
00:10
The first step involves the heating of ice which leads to increasing temperature from minus 40 to 0 degree celsius and next step is the melting of ice.
00:22
So q1 is calculated using the formula n c delta t where n is the moles of ice taken, c is the specific heat kept molar heat capacity of ice and delta t is the change in temperature.
00:41
Now we are given the mass of water not the moles of water.
00:44
So first of all we will calculate n.
00:48
N is moles which is equal to mass divided by molar mass of water which is 18 grams per mole.
00:55
So upon solving it we get n equal to 5 .56 moles.
01:03
Here we get 5 .56 moles.
01:06
C is this heat capacity of ice not water and it is given as 37 .7 joules per mole kelvin.
01:21
Delta t will be same whether the temperature is in celsius or in kelvin.
01:26
So it is equal to final temperature minus initial temperature.
01:33
So we get 5 .56 moles multiplied by 37 .7 joules per mole kelvin and this is 40 degree...