Calculate the enthalpy of reaction for: 6 H2 (g) + 4 C (s) + O2 (g) -> 2 C2H5OH (l) Given the following enthalpies of reaction: C2H5OH (l) + 3 O2 (g) -> 2 CO2 (g) + 3 H2O (l) ΔH = -875 kJ C (s) + O2 (g) -> CO2 (g) ΔH = -394.5 kJ 2 H2 (g) + O2 (g) -> 2 H2O (l) ΔH = -571.6 kJ