Calculate the entropy of vaporization per mole of substance Z whose enthalpy of vaporization is 14.6 kJ/ mol, and its boiling point is -87.7 oC. ∆Go = ∆Ho - T∆So 0.166 J/mol K 78.7 J/ mol K 166 J/mol K 6.02 J/mol K

Name: calculate the entropy of vaporization per mole of substance z whose enthalpy of vaporization is 146 kj mol and its boiling point is 877 oc go ho tso question 19 options 0166 jmol k 787 j mol k 166 jmo
Uploaded: 2023-06-29T00:13:13-08:00
Duration: 1 min 53 s
Channel: Lijeesh Krishnan
Description: calculate the entropy of vaporization per mole of substance z whose enthalpy of vaporization is 146 kj mol and its boiling point is 877 oc go ho tso question 19 options 0166 jmol k 787 j mol k 166 jmo

          Calculate the entropy of vaporization per mole of substance Z whose enthalpy of vaporization is 14.6 kJ/ mol, and its boiling point is -87.7 oC.  ∆Go = ∆Ho - T∆So

0.166 J/mol K

78.7 J/ mol K

166 J/mol K

6.02 J/mol K

Added by Yougot G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Lijeesh Krishnan

06/29/2023

Step 1

We do this by adding 273.15 to the Celsius temperature. So, -87.7 oC = 185.45 K. Show more…

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Calculate the entropy of vaporization per mole of substance Z whose enthalpy of vaporization is 14.6 kJ/ mol, and its boiling point is -87.7 oC. ∆Go = ∆Ho - T∆So 0.166 J/mol K 78.7 J/ mol K 166 J/mol K 6.02 J/mol K