00:01
Hello guys, so in this question we have to calculate the equilibrium concentrations of each compound at 298 kelvin.
00:07
So initial concentrations are given and firstly we have this reaction that is h2o plus cl2 when reacted it gives twice of hcl plus o2 that is oxygen.
00:20
We have been given the value of kc equal to 8 .96 multiplied by 10 to the power minus 9.
00:34
So what happens, the initial compound, initial concentration is given to us for h2o, that is 0 .030 molar.
00:44
And for cl2, it is given as 0 .105 molar.
00:48
And for xxion and oxygen will become 0.
00:51
So at equilibrium what happens, that the h2o concentration becomes 0 .30 minus x.
01:00
And this becomes, chlorine becomes 0 .105 minus.
01:05
X we have to also consider the m so let's multiply by m and write it so now what happens hcl becomes twice of x because of the stociometric or tumors of xcel and o2 becomes x now if you have to write the equilibrium constant expression in terms of kc we can write as concentration of o2 that is product o2 and xcel squared divided by the reactants that are h2 and cl2.
01:43
So here what happens? if we put these values, we get x multiplied by 2x square divided by 0 .030m minus x multiplied by 0 .105m minus x.
02:01
So from here, you can say that 0 .030m minus x is equal to 0 .030m and 0 .030m and 0 .050m...