calculate the grams of solute needed to prepare each of the following A. 4.00 L of a 0.250 M KCL solution B. 40.0 ml of a 7.00 M HCL solution
Added by Ray B.
Step 1
We need to find the moles of solute (KCl) needed for the solution. Moles of solute = Molarity × Volume of solution Moles of KCl = 0.250 M × 4.00 L = 1.00 mol Show more…
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