00:01
Here in this problem we have to calculate the h plus ion concentration and the ph of it 3 .79 times 10 to the power of negative 4 molar nitrous acid solution and ka of nitrous acid given here.
00:15
Now let's write the dissociation reaction for nitrous acid.
00:28
Now let's set up ice table.
00:30
Initial concentration given here 3 .79 times 10 to the power of negative 4 molar and initial concentration of the products 0 ,0.
00:41
Change concentration here it is positive x, positive x.
00:46
Equilibrium concentration 3 .79 times 10 to the power of negative 4 minus x.
00:54
Here 0 plus x, x, x.
00:56
Now let's write the expression for ka that will be concentration of the nitrate ions times the concentration of hydronium ions divided by the equilibrium concentration of the acid.
01:11
Here ka given 7 .10 times 10 to the power of negative 5...