00:01
Here in this problem we have to calculate the hydrogen ion concentration and ph of a 2 .97 times 10 to the power of negative 4 molar iodoacetic acid solution.
00:11
The ka of the acid given here.
00:14
Let us say the acid is ha weak acid and it dissociates in water as a - and h3o plus.
00:28
Now let us set up ice table.
00:31
Initial concentration given 2 .97 times 10 to the power of negative 4 molar and this is 0 0.
00:40
Change concentration negative x and here it will be positive x positive x.
00:47
Equilibrium concentration initial concentration minus change concentration here 0 plus x x also this one x.
00:58
Now let us write the expression for ka that will be concentration of a minus times concentration of hydronium plus divided by the concentration of the acid ha.
01:15
Here ka value given 6 .68 times 10 to the power of negative 5.
01:24
Concentration of a minus x this one also x so x square and equilibrium concentration of the acid is this one 2 .97 times 10 to the power of negative 4 minus x...