Question

Calculate the $\Delta H^\circ_{rxn}$ in the unit of kJ for $2CH_4(g) \rightarrow C_2H_4(g) + 2H_2(g)$ from the following information: (1) $2C_2H_6(g) + 7O_2(g) \rightarrow 4CO_2(g) + 6H_2O(l)$ $\Delta H^\circ = -3120.8$ kJ (2) $CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)$ $\Delta H^\circ = -890.3$ kJ (3) $C_2H_4(g) + H_2(g) \rightarrow C_2H_6(g)$ $\Delta H^\circ = -136.3$ kJ (4) $H_2(g) + \frac{1}{2}O_2(g) \rightarrow H_2O(l)$ $\Delta H^\circ = -285.8$ kJ

          Calculate the $\Delta H^\circ_{rxn}$ in the unit of kJ for $2CH_4(g) \rightarrow C_2H_4(g) + 2H_2(g)$ from the following information:
(1) $2C_2H_6(g) + 7O_2(g) \rightarrow 4CO_2(g) + 6H_2O(l)$  $\Delta H^\circ = -3120.8$ kJ
(2) $CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)$  $\Delta H^\circ = -890.3$ kJ
(3) $C_2H_4(g) + H_2(g) \rightarrow C_2H_6(g)$  $\Delta H^\circ = -136.3$ kJ
(4) $H_2(g) + \frac{1}{2}O_2(g) \rightarrow H_2O(l)$  $\Delta H^\circ = -285.8$ kJ

Calculate the Δ H^∘rxn in the unit of kJ for 2CH4(g) → C2H4(g) + 2H2(g) from the following information:
(1) 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(l) Δ H^∘ = -3120.8 kJ
(2) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) Δ H^∘ = -890.3 kJ
(3) C2H4(g) + H2(g) → C2H6(g) Δ H^∘ = -136.3 kJ
(4) H2(g) + (1)/(2)O2(g) → H2O(l) Δ H^∘ = -285.8 kJ

Added by Jason W.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Lazim D

03/21/2022

Step 1

Step 1: We need to find the enthalpy change for the given reaction: 2CH4(g) + 2O2(g) → 2CO2(g) + 4H2O(l) Show more…

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Calculate the ΔH in the unit of kJ for 2CH4(g) + 2O2(g) → 2CO2(g) + 4H2O(l) from the following information: (1) 2CH4(g) + 7O2(g) → 4CO2(g) + 8H2O(g) ΔH = -3120.8 kJ (2) CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) ΔH = -890.3 kJ (3) CO2(g) + H2O(g) → CO2(g) + H2O(l) ΔH = -136.3 kJ (4) H2(g) + O2(g) → H2O(l) ΔH = -285.8 kJ