00:01
We are asked to calculate the heats of combustion using thermodynamic data.
00:07
And i'm going to make a note to yourself, a note to you, that you need to double check and make sure you've got the right things here.
00:17
So i'm looking this one up.
00:18
This one is negative 285 .83 and watch for the liquid there.
00:25
This is zero and this is zero.
00:27
So my heat of combustion will be equal to two moles times negative 285 .83 kilojoules per mole, which i should have written right here, minus, and then we'll have two times zero plus one times zero.
01:06
So this will equal negative 285 .83 times two.
01:14
This one is negative 571 .66 kilojoules.
01:21
Let me get back to the question and see what this looks like.
01:26
So it wants kilojoules per mole, kilojoules, and that will be, so it's negative 571 .66 kilojoules for the reaction.
01:58
And i want to make a note here, it says kilojoules per mole.
02:04
So per mole of what? if it's h2o -l, then the answer is negative 285 .83 kilojoules per mole of h2o -l...