Calculate the ΔHrxn for the process:
Zn (s) + 1/8 S8 (s) + 2O2 (g) → ZnSO4 (s)
From the following information: Zn (s) + 1/8S8 (s) → ZnS (s) ΔH1 = -183.92 kJ
2ZnS(s) + 3O2 (g) → 2ZnO(s) + 2SO2 (g) ΔH2 = -927.54 kJ
2SO2 (g) + O2 → 2SO3(g) ΔH3 = -196.04 kJ
ZnO (s) + SO3 (g) → ZnSO4 (s) ΔH4 = -230.32 kJ