Question

Calculate the index of refraction of a glass with thickness 6, rotated through an angle of 5. When light with wavelength 852 pass through it. Assume 214 interference rings are counted.

          Calculate the index of refraction of a glass with thickness 6, rotated through an angle of 5. When light with wavelength 852 pass through it. Assume 214 interference rings are counted.
        
Calculate the index of refraction of a glass with thickness 6, rotated through an angle of 5. When light with wavelength 852 pass through it. Assume 214 interference rings are counted.

Added by Jennifer S.

Close

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
Calculate the index of refraction of a glass with thickness 6, rotated through an angle of 5, when light with wavelength 852 nm passes through it. Assume 214 interference rings are counted.
Close icon
Play audio
Feedback
Powered by NumerAI
Kathleen Carty Ivan Kochetkov
David Collins verified

Mark J and 58 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
calculate-the-critical-angle-for-total-internal-reflection-for-light-traveling-from-a-particular-typ

Calculate The critical angle for total internal reflection for light traveling from a particular type of glass to air is $39.1^{\circ}$. What is the index of refraction of this glass?

Pearson Physics

calculate-the-angle-of-refraction-for-light-as-it-passes-from-air-to-each-of-the-mediums-at-an-incidence-angle-of-258-water-n-133-b-diamond-n242-plexiglas-n151-5-a-ray-of-light-travels-from-97527

Calculate the angle of refraction for light as it passes from air to each of the mediums at an incidence angle of 25°. a. Water (n=1.33); b. Diamond (n=2.42) c. Plexiglas (n=1.51) 5. A ray of light travels from air into glass. The ray enters the glass at an angle of 36° from the normal. If the index of refraction for glass is 1.5, determine the angle of refraction.

Kelan H.

consider-crown-glass-with-the-dispersive-refractive-index-n15580070-n-1558-0070-where-is-the-wavelength-in-microns-find-the-angle-in-radians-of-total-internal-reflection-of-the-crown-glass-i-39064

Consider crown glass with the dispersive refractive index n=1.558−0.070λ n = 1.558 − 0.070 λ , where λ λ is the wavelength in microns. Find the angle (in radians) of total internal reflection of the crown glass in air for visible light with wavelength 494 nm.

Madhur L.


*

Recommended Textbooks

-
University Physics with Modern Physics

University Physics with Modern Physics

Hugh D. Young 14th Edition
achievement 1,192 solutions
Physics: Principles with Applications

Physics: Principles with Applications

Douglas C. Giancoli 7th Edition
achievement 1,136 solutions
Fundamentals of Physics

Fundamentals of Physics

David Halliday, Robert Resnick , Jearl Walker 10th Edition
achievement 1,188 solutions

*

Transcript

-
00:02 So this question involves total internal reflection.
00:08 To understand the question, let's talk about what that means.
00:12 Let's say we have an interface between two materials.
00:18 In this case, we're going from glass to air, and glass will have a higher index refraction than air does.
00:36 So when a light ray is incident on this interface, the direction of travel of the light ray will bend away from the normal line.
00:56 And the angles we use are those defined by, as i said, the normal line, which is this line here, the line that is normal to the interface between the two substances.
01:11 So the angle out here in the air is bigger than the angle in here in the glass.
01:20 So this is the incoming light ray hits the interface, and this is the refracting light ray here.
01:29 Now, because it's bending away from the normal, what can happen if you go in at a big enough angle is the following.
01:38 Let us say that we go into an even bigger angle to the interface.
01:46 The incident light is at an even bigger angle to the interface.
01:55 So it's like this, and that angle is so big that the angle of refraction is 90 degrees.
02:07 We'll just draw that here, if i can.
02:19 There we go.
02:23 Well, that means the light's not being refracted then.
02:26 If the angle of refraction is 90 degrees, then the light isn't really refracting.
02:31 It's just staying inside of the glass.
02:34 In fact, what happens when light is incident on a interface here is that usually it's a combination of both reflection and refraction.
02:46 But here, none of the light can be refracted because it can't get out of the medium.
02:53 The angle that it's making in the air is 90 degrees.
02:58 So what actually happens is all the light then gets reflected.
03:01 And of course, we know when light is reflected, the rule we follow is different.
03:05 It's just the angle of incidence equals the angle of reflection.
03:08 So the light's going to be reflected back in...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever