00:01
Hi students, here in the question first we need to find the magnetic field at the location of the electron.
00:07
For that we will use the formula b is equals to mu0 i upon 2 pi r.
00:16
So b is the magnetic field, mu0 is the permeability of free space, i is the current.
00:23
So if we solve for b here, we get b is equals to mu0 that is 4 pi into 10 to the power minus 7 into current that is 10 ampere upon 2 pi into r that is 0 .05 meter.
00:39
When we solve it, we get value of b as 1 .26 into 10 to the power minus 5 tesla.
00:46
Next we need to find the velocity of the electron and we know that it is moving perpendicular to the magnetic field.
00:52
So it will experience a magnetic force.
00:54
We will use the formula for that f is equals to qvb and from here when we will solve it for v, we will get the values.
01:09
Now f is the magnetic force, q is the charge of the particle here.
01:12
The charge of an electron is 1 .6 into 10 to the power minus 19 coulomb...