Calculate the magnitude of the electrostatic attraction force between an electron and a proton at a distance of 5.29x10^-11 m in a hydrogen atom.
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6 \times 10^{-19} \, \text{C} \) (charge of an electron) - \( Q_2 = 1.6 \times 10^{-19} \, \text{C} \) (charge of a proton) - \( r = 5.29 \times 10^{-11} \, \text{m} \) (distance between the electron and proton) Show more…
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