Calculate the magnitude of the normal force on a 12.7 kg block in the following circumstances. (Enter your answers in N.) HINT (a) The block is resting on a level surface. 124.48 The four cases in this problem are the most common situations. In general, solving for the normal force involves drawing a free-body diagram and applying Newton's second law. N (b) The block is resting on a surface tilted up at a 25.8° angle with respect to the horizontal. 97.76 N (c) The block is resting on the floor of an elevator that is accelerating downward at 4.28 m/s². 178.816 N (d) The block is on a level surface and a force of 175 N is exerted on it at an angle of 25.8° above the horizontal. 234.513 N
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So, we have: $N = mg$ where $m = 12.7\,\text{kg}$ and $g = 9.81\,\text{m/s}^2$. Plugging in the values, we get: $N = 12.7\,\text{kg} \times 9.81\,\text{m/s}^2 = 124.48\,\text{N}$ Show more…
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