00:01
Consider the equation i've written on the top of this page.
00:04
That was provided it is a balanced chemical equation.
00:08
And i have written down the molar masses for each of our three species.
00:13
We're given that we have 12 .00 grams of aluminum and we're reacting that with 10 .00 grams of 02.
00:29
Eventually we're told that our actual yield is, two grams of aluminum oxide.
00:48
We are asked to find the theoretical yield, the limiting reactant, and from those in this, we're asked to find the percent yield.
01:14
So we have three things that we're asked to find.
01:17
Let's begin.
01:23
I'm going to convert each of these values to grams of aluminum oxide, because i'll need that later.
01:38
My first step in a mass mass conversion is to convert mass of given.
01:41
To moles of given.
01:46
My second step is to convert my moles of given to my moles of my unknown.
02:05
What am i doing there? why did i put that second two in there? because i'm losing my mind.
02:14
And finally, we'll convert that to grams of product.
02:33
Let's see what this equals.
02:35
Let me get my calculator...