Calculate the mass percent by volume of 42.5 g of glucose (C6H12O6, MM = 180.2 g/mol) in 325 mL of solution.
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Step 1
First, we need to find the moles of glucose. To do this, we'll use the formula: moles = mass / molar mass moles = 42.5 g / 180.2 g/mol moles ≈ 0.236 mol Show more…
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