00:01
Hello, here we have to calculate maximum displacement of the spring, which is compressed if the mass of 2 kilograms is released from the rest.
00:16
And then slide down the distance d of 200 centimeters before coming in contact with the spring.
00:32
The spring has a constant of 100 newton meter.
00:36
And g is 10 meters per second squared.
00:51
Let's illustrate it.
01:09
So initially the system had only potential energy, which is a gravitational potential energy.
01:23
So let's introduce y -axis and let's locate zero here at the uncompressed spring.
01:32
So therefore that's distance.
01:33
This potential energy is mg d times sine theta and when spring is compressed its potential the potential energy of the block is negative mg x times sine theta and potential energy of the spring is k x squared over 2 therefore m g d times sine theta equals to k x squared over 2 minus m g x sine theta.
02:29
So on here we of course have to calculate x...