Calculate the maximum number of moles and mass of iodic acid (HIO3) that can form when 735 g of iodine trichloride reacts with 107.7 g of water. What mass of excess reagent remains? 2 ICl3 + 3 H2O --> ICl + HIO3 + 5 HC
Added by Bryan S.
Step 1
Given: - Mass of ICl3 = 735 g - Molar mass of ICl3 = 233.24 g/mol - Mass of H2O = 107.7 g - Molar mass of H2O = 18.015 g/mol Moles of ICl3 = 735 g / 233.24 g/mol = 3.15 mol Moles of H2O = 107.7 g / 18.015 g/mol = 5.98 mol Show more…
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