00:03
Here in this problem, given 13 .3 gram of sucrose is dissolving 276 gram of water.
00:11
We have to find out the molality of the solution.
00:15
Now, first find out the mole of sucrose.
00:19
Mole of sucrose in 13 .3 gram of sucrose.
00:28
So, mole of sucrose will be the mass given here, 13 .3 gram.
00:33
Let's write that.
00:34
Divided by the molar mass of sucrose which is given 342 .3 gram per more.
00:45
And if we divide, we get 0 .0389 more.
00:52
Now, mass of solvent, that is mass of water given here, 276 gram.
01:00
So let's write this, mass of solvent given 2006...