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Hello students, in this question we have to find out the molar change in the chemical potential of the ideal gas when the gas expands 10 times of the original volume.
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Let the original volume be v1 and the v2 will be equal to 10 times of v1.
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For the expansion process, the pressure and the temperature remains constant.
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Now we are going to use the ideal gas equation pv is equal to nrt.
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V by n will be equal to rt by p, this is equal to constant.
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Therefore, v1 by n1 will be equal to v2 by n2.
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Substituting the value, v1 by n1 will be equal to 10 times of v1 divided by n2.
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V1 v1 cancels each other.
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On solving this we will get n2 will be equal to 10 times of n1...