Calculate the molarity of an acetic acid solution if 29.3 mL of an HC2H3O2 solution is titrated with 26.0 mL of a 0.183 M KOH solution: HC2H3O2(aq) + KOH(aq) → H2O(l) + KC2H3O2(aq) Express your answer with the appropriate units. Molarity =
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Step 1
First, we need to find the moles of KOH used in the reaction. We can do this by multiplying the volume of KOH solution by its molarity: moles of KOH = volume of KOH solution × molarity of KOH solution moles of KOH = 26.0 mL × 0.183 M Since 1 L = 1000 mL, we need Show more…
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