Calculate the mole fraction of water in a mixture of 12 g water, 108 g acetic acid, and 92 g ethyl alcohol.
Added by Samantha T.
Step 1
The molar mass of water (H2O) is approximately 18 g/mol, acetic acid (CH3COOH) is approximately 60 g/mol, and ethyl alcohol (C2H5OH) is approximately 46 g/mol. So, the number of moles of each component is: Water: 12 g / 18 g/mol = 0.67 moles Acetic acid: 108 g Show more…
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