Calculate the molecular mass of the nonionic solutes. 64.3 grams of solute in 3.90 X 102 grams of water raises the boiling point to 100.680 °C. g/mol
Added by Christopher T.
Step 1
First, we need to find the molality (m) of the solution using the boiling point elevation formula: ΔTb = Kb * m where ΔTb is the change in boiling point, Kb is the boiling point elevation constant for water (0.512 °C/molal), and m is the molality of the Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 73 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If $291 \mathrm{~g}$ of a compound is added to $1.02 \mathrm{~kg}$ of water to increase the boiling point by $5.77^{\circ} \mathrm{C}$, what is the molar mass of the added compound? (Assume a van 't Hoff factor of 1.) $\begin{array}{lll}31.1 \mathrm{~g} / \mathrm{mol} & 30.3 \mathrm{~g} / \mathrm{mol}\end{array}$ $\begin{array}{ll}28.5 \mathrm{~g} / \mathrm{mol} & 18.3 \mathrm{~g} / \mathrm{mol}\end{array}$ $25.3 \mathrm{~g} / \mathrm{mol}$ a.$31.1 \mathrm{~g} / \mathrm{mol}$ c.$28.5 \mathrm{~g} / \mathrm{mol}$ b.$30.3 \mathrm{~g} / \mathrm{mol}$ d$18.3 \mathrm{~g} / \mathrm{mol}$ e.$25.3 \mathrm{~g} / \mathrm{mol}$
The molar mass of a nonelectrolyte is 58.0 $\mathrm{g} / \mathrm{mol}$ . Determine the boiling point of a solution containing 35.0 $\mathrm{g}$ of this compound and 600.0 $\mathrm{g}$ of water. The barometric pressure during the experiment was such that the boiling point of pure water was $99.725^{\circ} \mathrm{C}$ .
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD