00:01
Hi this is a question based on momentum.
00:03
So, in this we are given with three conditions.
00:06
So, we have for so first condition for v is equal to 0 .01 c we have to calculate y which is the lorentz factor.
00:15
So, we given by 1 by root of 1 minus v square by c square which is equal to 1 divided by root of so 1 minus 0 .01 c square divided by c square c square c square get cancelled we have 1 .00005 is the lorentz factor.
00:34
Now we can have the momentum as m into v.
00:37
So, m is the rest mass of the proton which is 1 .67 into 10 power minus 27 into 1 .00005.
00:46
So, we have momentum p so into velocity.
00:49
So, we have p is equal to m into m into lorentz factor into v.
00:55
So, velocity is 0 .01 c.
00:58
So, from this calculation we have p is nearly equal to so c is 3 into 10 power 8 1 .67 into 10 power minus so 1 .67 into 10 power minus 27 kg meter per second.
01:12
So, here we have 1 kg meter per second is 5 .06 into 10 power 90 mega electron volt per coulomb.
01:23
So, this much amount of kg meter per second is equal to it is 1 .67 into 10 power minus 29 divided by 5 or into so into so this is multiplied by 5 .06 into 10 power minus 10 power plus 19 mega electron volt per c.
01:48
So, we have the answer as it is 8 .45 mev per c.
01:54
This is the first part.
01:55
In the second part we have v is equal to so in the second part we have v is equal to 0 .5 c.
02:03
So, first let us consider the lorentz factor which is 1 by root of 1 minus v square by c square that is 0 .5 square divided by c square into c square.
02:12
So, c square c square get cancels we have 1 .155.
02:16
Then we have p is equal to gamma into m into v m naught into v...