00:01
Hi, in this question we have been given we have a metal that is 93 and d and the atomic weight of this is 93 gram and the density is 8 .57 gram per centimeter cube.
00:21
So, as we know that fermi energy is given by h divided by 2m 3 pi square n divided by v whole raised to the power 2 divided by 3.
00:40
There n is number of particles, then m is mass of each particle, h is planck's constant and v is volume of the system.
01:02
So here, first of all we will calculate this n divided by v.
01:06
So this is equal to n a multiplied by density divided by mass of the atom.
01:13
So this will be equal to 6 .022 multiplied by 10 raised to the power 23 which is a avogadro number multiplied by 8 .57 density divided by 93.
01:27
So this will be in atoms per centimeter cube.
01:35
So on solving this we will get n by d equal to 5 .54 times 10 raised to the power 22 atoms per centimeter cube.
01:46
So if you convert this in meter form, so n divided by d will be 5 .54 times 10 raised to the power 28 atoms per centimeter cube.
01:59
So here we have calculated n divided by d...