Calculate the net electric field Ep^net (magnitude and...

Calculate the net electric field E_p^net (magnitude and direction) at P -the point at the center of a square of side 2 cm with charges at the corners. For full credit, draw and label the direction of the electric field vectors due to each charge (i.e. E1P, E2P, E3P, and E4P). Use the coordinate system in the figure. You may draw the same figure on a separate page and label. q1= -1 ?C q2= +2 ?C q3= -3 ?C q4= -1.5 ?C s= 2 cm

Transcript

00:01 This problem we have given a square like this and this is suppose q1 which is equal to minus one microculum this is q2 which is equal to two microculum this is q3 which is equal to minus three micropoleum and this is q4 which is minus 1 .5 microtum this is the center of this square we have to find we have to find the net electric field on this origin or this point p so due to q1 the direction of net electric field this is e1p due to 2 this is e2p due to 3 this is e 3p and due to 4 it is e 4 p so first we know that this distance are for equal this is from center to the corner distance r it is equal to this distance is equal to r which is equal to the side length of this square is given to us which is two centimeters so this will be equal to one centimeter and this is one so we can write r is equal to under root two so we can write even p is equal to k q1 by r square this is k into q1 is one microculum this is one into ten to the power minus six divided by two now e3p will be equal to k into three into ten to the power minus six divided by two so the net electric field in this direction will be equal to e3p minus e1p this is equal to two k into ten to the power minus six divided by two now we will find e2 p and e4p e2 p e2 p will be equal to k q2 by r square which is 2 this is k into q2 is 2 microcule arm so this is 2 into 10 to the power minus 6 divided by 2 and e 4p will be equal to k q 4 by r square which is 2 this is k into q 4 the value of q 4 is 1 .5 into 10 to the power minus 6 divided by 2 so the net e 2 p plus e 4 4p is equal to 3 .5k into 10 to the power minus 6 divided by 2.

03:55 So if we see the diagram, we can see that this is supposed point p.

04:00 So here in this direction, net electric field is e2p plus e 4p.

04:10 And due to q1 and q3, net electric field is in this direction...

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