00:01
According to the henderson -hasselbalch equation, ph equals pca plus the log of the moles of the base, which i'll just call x over the moles of the acid y.
00:17
So if our ph is going to be 7 .4 and our pca is 7 .21, then we can solve for the ratio of the moles of base over the moles of acid.
00:36
If i subtract 7 .21 from both sides, i get .19.
00:41
I then take the anti -log base 10 of both sides, and i get 1 .549 is equal to the moles of base over the moles of acid.
00:55
Well, how many total moles do i need? well, i want to prepare a 1 .7 molar 200 milliliters.
01:05
So, 200 milliliters is 0 .2 .00 liters.
01:12
Molarity times volume and liters gives us the total moles that we need.
01:19
So that's going to be 0 .340 moles.
01:28
So i know that x plus y is equal to the total moles.
01:33
0 .340.
01:40
And i also know that the ratio of the two is this.
01:44
So i've got two equations and two unknowns.
01:47
So y can be expressed in terms of x is 0 .340 minus x...