Calculate the number of oxygen atoms in a 140.0 g sample of iron(III) oxide (Fe2O3). Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.
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Given: Molar mass of Fe = 55.8 g/mol Molar mass of O = 16.0 g/mol Molar mass of Fe2O3 = (2 * molar mass of Fe) + (3 * molar mass of O) Molar mass of Fe2O3 = (2 * 55.8 g/mol) + (3 * 16.0 g/mol) Molar mass of Fe2O3 = 111.6 g/mol + 48.0 g/mol Molar mass of Fe2O3 = Show more…
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