00:01
Hello students, welcome here in this question we have a sodium saccharine.
00:07
Sodium saccharine is reacting with.
00:13
So how much this one is given 10 mol of sodium saccharine is reacting with iodine.
00:26
Iodohethane.
00:28
This one is a 0 .88m.
00:31
In presence of dmf which is 5 ml is given.
00:38
So to give, so which product here it will form is our product will form here.
00:47
So here in this question we had to find out the yield, theoretical yield and percentage of yield.
01:05
And also purity of the reactants of the compound as well as we have to find out here.
01:24
So as if you see the reaction here we will see the reaction sodium sarahin.
01:32
How can you write here it is double bond o double bond this one is s double bond dauvon -o -e -n and this one is minus here and a plus and here there are two dull -vons or the dull -ons as benz in final ring and each is reacting with ido ethan so ethan is ch3, ch2, i, ido ethan in presence of dmf so 5 mleds and the product will be so the substitution here it will take place.
02:21
Here, n is there, here w and o.
02:24
Here this methyl group, so it is plus and it is positively negative charge because bond is migrates towards this side because the electronegativity of iodine is more when compared with carbon.
02:40
So here it is positive.
02:42
So this bond will be attacked here.
02:46
Then here it is ch2, ch3 and n -a -i will produce.
02:54
Now the yield how can you calculate? the molar mass of sodium saccharine is 205 .17 grams and here it is iodine 155 .97 grams per mole and the molar mass of the product is 1 .125 .10.
03:16
11 .24.
03:19
Okay, so this one is the main product.
03:22
Now the next compound here it is we will see the so here it is given 10 mole is given and here it is 0 .88 ml is given so when ml we have we can calculate the mass as we know the density so it is volume is given.
03:48
Given here and density of iodomethine is 1 .94.
03:54
So mass is equal to volume multiplied by density.
03:59
So mass is equal to here it is approximately 1 .707 grams here.
04:12
Now the reaction here we will see here, product, how much here produced...