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Starting with first question a.
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Molar mass of copper sulfate, cuso4 -5h -2o, equal to 63 .5, multiplied with 1 plus 32, multiplied with 1 plus 16, multiplied with 4 plus 5, multiplied with 80.
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Simplification, we are going to get 249 .5 grams per mole.
00:40
Percent h2o equal to part h2o divided by whole compound multiplied with 100.
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Let us substitute the values here.
01:00
Part of h2o is 70.
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Whole compound is 249 .5 grams per more, multiplied with 100.
01:12
Percent h2o is equal to 36 .07 percent.
01:20
Hence the answer for the first question is percent h -2o is equals to 36 .07 percent.
01:30
Next question b, mg, so4, 7h -2.
01:37
Molar mass equal to 24 multiplied with 1, plus 32 multiplied with 1, plus 16 multiplied with 7, plus 16 multiplied with 7, plus 7 multiplied with 18.
01:59
Simplification uses 276 grams per mole percent h2o is equals to part h2o divided by whole compound multiplied with 100 part h2o 126 276 is the whole compound multiply with 100 and simplify it we are going to get 51 point to 1 % this is percent h2o answer for b is 51 .2 percent.
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C.
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C.
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C .l...