00:01
In this question we are assigned with the task to calculate the ph value of a mixture of sodium hydroxide and the weak acid astic acid.
00:12
In the mixture we have 12 .50m of 0 .10m of 0 .10 molar n .a .h and 25m of 0 .10 molar ashtic acid.
00:28
So the number of moles of nih and number of moles of astic acid is calculated.
00:34
0 .1 moles in 1000 ml.
00:37
So the number of moles in 12 .50m.
00:40
Similarly, it is done for ashtic acid as well.
00:43
So know the number of moles of both present in the mixture.
00:48
It is 1 .25 into 10 to the power minus 3 moles.
00:53
2 .5 into 10 to the power minus 3 modes of astic acid is present.
00:57
The reaction of ashtic acid with sodium hydroxide is shown here.
01:01
Astic acid reacts with sodium hydroxide to give ch3 coo minus.
01:07
Here we are not considering the sodium ion and water is formed.
01:11
Now let us construct the i -ze table to find out the equilibrium concentration.
01:16
Sorry, the final concentration of ashtic acid.
01:20
Initial concentration of ashtic acid is 2 .5 into 10 to the power minus 3 more.
01:26
And the number of moles of sodium hydroxide taken is 1 .25 into 10 to the power minus 3.
01:32
The sodium hydroxide and the initial concentration of acetate is 0 and water is also 0.
01:38
Now let us consider that all the sodium hydroxide taken will react completely with the acic acid.
01:46
Hence the change is minus 1 .25 into 10 to the power minus 3 and for sodium hydroxide also it is same and the amount of acetate produces 1 .25 into 10 to the power minus 3.
01:58
Now let us give the equilibrium concentration.
02:00
It is 0 for sodium hydroxide, 1 .25 into 10 to the per minus 3 for acetate...