Calculate the pH at the equivalence point in the titration of 50.0 mL of 0.100 M CH3COOH (Ka = 1.8 ×10-5 ) with 0.100 M NaOH
Added by Cesar B.
Step 1
At the equivalence point, the moles of CH3COOH and NaOH are equal. So, let's calculate the moles of CH3COOH in the solution: moles of CH3COOH = volume × concentration moles of CH3COOH = 0.050 L × 0.100 mol/L = 0.005 mol Show more…
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