Calculate the pH of 0.180 M NH3 if Kb of NH3 is 1.8 x 10-5. Equation is NH3 (aq) + H2O (l) <--> NH4+ (aq) + OH- (aq) If you don't want to lose points present pH with one unit after the decimal point, yep just one unit after the decimal point.
Added by George L.
Step 1
Write the Kb expression for the reaction: Kb = [NH4+][OH-] / [NH3] Show more…
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