00:01
Hi, so to solve for this, i need to write first our ice table.
00:06
Hclo, hyperchlorous acid, this will dissociate to h plus and clo minus initial change, equilibrium concentration.
00:16
The initial concentration is 0 .0129 molar.
00:21
Products are 0 initially.
00:22
This will lose some amount.
00:23
This will gain.
00:24
This will gain.
00:25
At the equilibrium, we have 0 .0129 minus x.
00:29
This will be x and x.
00:32
And how do we solve for the ph? we need to find the value of the hydrogen ion concentration at equilibrium, which is equivalent to x.
00:39
So we need to solve for the value of x first.
00:42
We will use the given ka.
00:44
Remember that ka is equivalent to the concentration of the products at equilibrium.
00:49
We have h plus and clo minus over the concentration of the reactant hclo.
00:56
Plug in the information that we have.
00:58
Ka is 2 .9 times 10 to the negative 8...