00:01
Okay, so this question is about calculating the ph deba buffer solution.
00:07
So you have two compound, which is sodium h2po4, and another is sodium 2, hpo4.
00:20
So from here, you see, one has more protons, so this would be the conjugate acid, and this would be the conjugate base.
00:28
Right and it tells us where you have about 8 .5 grams of this another you have about 10 .1 .8 grams so from here what we can calculate is the more of the conjugate acid here right the conjugate acid would be equal to the 8 .5 grams over the more mass is 1 .5 grams is 1 .5 .5 grams is 1 .5 1 .3a grams per more, which will be equal to about 0 .0616.
01:18
And for the conjugate base, the sodium 2 hydrogen phosphates be equal to 10 .18 over the 268, which will be equal to 0 .0380, is 0.
01:49
And then we need to calculate the ph of the mixture, right? actually, we don't need the volume here because if we look at that, the ph equals to the pca minus log, right, the concentration of the acid over the concentration of the base.
02:10
So the concentration of the acid is equal to the mores of the acid, right, over the volume.
02:26
And the concentration of the base is more of the base over the volume...