Question

Calculate the pH of a buffer that is a mixture of 0.37 M ammonia and 0.15 M ammonium chloride Calculate the pH after 2.5 mL of 0.43 M HBr is added to 250 mL of this buffer, giving a solution with a volume of 252.5 mL For comparison, calculate the pH after 2.5 mL of 0.43 M HBr is added to 250 mL of an unbuffered solution with a pH of 9.65. The volume of the final solution is 252.2 mL

Name: calculate the ph of a buffer that is a mixture of 037 m ammonia and 015 m ammonium chloride calculate the ph after 25 ml of 043 m hbr is added to 250 ml of this buffer giving a solution with 89557
Uploaded: 2021-12-31T13:36:08-08:00
Duration: 5 min 11 s
Channel: Raghvendra Singh
Description: calculate the ph of a buffer that is a mixture of 037 m ammonia and 015 m ammonium chloride calculate the ph after 25 ml of 043 m hbr is added to 250 ml of this buffer giving a solution with 89557

          Calculate the pH of a buffer that is a mixture of 0.37 M ammonia
and 0.15 M ammonium chloride
Calculate the pH after 2.5 mL of 0.43 M HBr is added to 250 mL
of this buffer, giving a solution with a volume of 252.5 mL
For comparison, calculate the pH after 2.5 mL of 0.43 M HBr is
added to 250 mL of an unbuffered solution with a pH of 9.65. The
volume of the final solution is 252.2 mL

Added by Miguel M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Raghvendra Singh

12/31/2021

Step 1

Given: \[ [\text{NH}_3] = 0.37 \, \text{M} \] \[ [\text{NH}_4\text{Cl}] = 0.15 \, \text{M} \] Using the Henderson-Hasselbalch equation: \[ \text{pH} = \text{p}K_{\text{a}} + \log\left(\frac{[\text{NH}_4\text{Cl}]}{[\text{NH}_3]}\right) \] \[ \text{pH} = 4.75 + Show more…

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Calculate the pH of a buffer that is a mixture of 0.37 M ammonia and 0.15 M ammonium chloride Calculate the pH after 2.5 mL of 0.43 M HBr is added to 250 mL of this buffer, giving a solution with a volume of 252.5 mL For comparison, calculate the pH after 2.5 mL of 0.43 M HBr is added to 250 mL of an unbuffered solution with a pH of 9.65. The volume of the final solution is 252.2 mL