Calculate the pH of a solution formed by mixing 250.0 mL of 0.900 M NH4Cl with 250.0 mL of 1.60 M NH3. The Kb for NH3 is 1.8 Ă— 10^-5
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Given: 250.0 mL of 0.900 M NH4Cl Moles of NH4Cl = 0.900 mol/L * 0.250 L = 0.225 mol Show more…
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