Calculate the pH of a solution that is 0.178 M in nitrous acid (HNO2) and 0.322 M in potassium nitrite (KNO2). The acid dissociation constant (Ka) of nitrous acid is 4.50 × 10?? A. 14.26 B. 3.604 C. 3.093 D. 10.91 E. 4.589 If a patient's blood has a pH of 7.3 the patient has a condition called A. diabetes B. acidosis C. alkalosis D. hypertension E. none of the above, the pH is normal
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50 x 10^-4 pKa = -log(Ka) = -log(4.50 x 10^-4) = 3.346 Show more…
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