Calculate the pH of the buffer formed by combining 150.0 mL of 0.10 M benzoic acid (C7H6O2) with 100.0 mL of 0.30 M sodium benzoate (NaC7H5O2). Benzoic acid has a Ka of 6.5 x 10-5. 9.69 4.49 10.51 4.19 4.31
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First, we need to find the moles of benzoic acid and sodium benzoate. moles of benzoic acid = 0.10 M * 0.150 L = 0.015 moles moles of sodium benzoate = 0.30 M * 0.100 L = 0.030 moles Show more…
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