00:02
Hello guys, so in this question we have to calculate the ph value of 0 .02 molar solution of hno3 and ph of 0 .05 molar solution of naoh.
00:21
Also we have to calculate the ph value obtained after mixing 75 ml of acid solution with 25 ml base.
00:36
So firstly for the first one hno3 we have been given the molarity of h plus so concentration of h plus is equal to 0 .002 molar which is equal to 2 multiplied by 10 to the power minus 3.
00:56
Formula is minus of log of concentration of h plus to find ph.
01:05
So if you put the value in this minus of log of 2 multiplied by 10 to the power minus 3.
01:12
We will get our ph value which is equal to 2 .699.
01:18
So this is the answer of the ph of h no3.
01:22
Next we have to find us ph of 0 .05 molar of n -o -h.
01:28
So again in this ph is equal to minus of log of concentration of h plus or we can write if we have to find firstly poh so it will be minus of log of oh h minus so this will be p -o -h.
01:49
So here, poh value is 0 .05, so minus log of 5 multiplied by 10 to bar minus 2.
02:02
This will give us the value of poh that is 1 .3011.
02:06
Now to find the ph, ph plus poh is equal to 14.
02:13
So here, ph will be equal to 14 minus 1 .301...