Calculate the pH when 47.0 mL of 0.1M NaOH is titrated with 57.9 mL of 0.090M HCl.
Added by Belinda J.
Step 1
Calculate the moles of NaOH and HCl. Moles of NaOH = (Volume of NaOH in L) × (Concentration of NaOH in mol/L) Moles of NaOH = (0.047 L) × (0.1 mol/L) = 0.0047 mol Moles of HCl = (Volume of HCl in L) × (Concentration of HCl in mol/L) Moles of HCl = (0.0579 L) × Show more…
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