The component of the car's weight acting against the slope is \(950 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times \sin(2.00^\circ)\). Therefore, the total force acting against the car is \(600 \, \text{N} + 950 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times
Show more…