Calculate the quantity of heat absorbed by 20 g of water that warms from \( 30^{\circ} \mathrm{C} \) to \( 90^{\circ} \mathrm{C} \). Express your answer in calories.
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- Mass of water (\(m\)) = 20 g - Initial temperature (\(T_i\)) = \(30^{\circ} \mathrm{C}\) - Final temperature (\(T_f\)) = \(90^{\circ} \mathrm{C}\) - Specific heat capacity of water (\(c\)) = 1 cal/g°C Show more…
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