Calculate the quantity of heat needed to change 250.0 g of ice at-25.0 degree C into super-heated at 250.0 degree C.
Added by Kayla C.
Step 1
0 g of ice at -25.0°C into water at 0°C. Given: Mass of ice, m = 250.0 g Latent heat of fusion of ice, L = 334 J/g Q1 = m * L Q1 = 250.0 g * 334 J/g Q1 = 83500 J Show more…
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