00:01
Hi, in this question, admittance is given, we have to find resistance, inductance and capacitance for the circuit.
00:07
Now, for the first case, we have admittance y is equal to 0 .25 plus j into 0 .6 simons, where this is conductance and this is suspectants.
00:20
We are given with z is equal to 1 by y.
00:23
So which becomes 1 divided by 0 .25 plus j into 0 .6.
00:30
So on rationalizing, this becomes equal to multiplied by 0 .25 minus j into 0 .6 divided by 0 .25 minus j into 0 .6.
00:44
So on solving this term, we have z is equal to 0 .25 minus j into 0 .6 divided by.
00:55
So this becomes a square minus b square and equating that the whole term will be equal to 0 .4225.
01:02
Therefore r is equal to 0 .25 divided by 0 .4225 which is equal to 0 .59 om and the capacity reactants is 0 .6 divided by 0 .425 which is equal to 1 .42 and we have the relation between capacity reactants and the capacitance given by c is equal to 1 by 2 .5.
01:38
So on substitution we have c is equal to 2 .23 millie ferret.
01:44
Similarly, we have the second case admittance given by y is equal to 0 .05 minus j into 0 .1 simon.
01:52
So we have z is equal to 1 by y...