00:01
Hi, let's have a look at the answer for this question.
00:03
So, now we have been given p .b.
00:07
Cr .o4, which is in solid state will be formed an equilibrium.
00:13
So the equation will be pb plus 2, which is in aqueous solution, which is like aqueous solution, less.
00:22
We get cro4, 2 minus, which is also in aquaure state.
00:28
And the solubility product that is ksp will be equals to 2 .8 into 10 to the power of minus 13 so this is the solubility product so now we have to find the solubility product so that is we can say that ksp will be equals to the concentration of p b plus 2 and the concentration of cr over minus 2 so this will be the solubility product as we know so we also know that the solubility product is given that is 2 .8 into 10 to the power of minus 13 so that is equals to we can say s into s so that is equals to s square here we can say if we apply root on both sides then we get a answer of here 5 .29 into 10 to the power of minus 7 equals we will get s as the root and square will cancel.
01:33
So now coming to the point here, solubility product of, that is s, is equal to 5 .3, almost equal to 5 .3.
01:45
So we can add 5 .3 into 10 to the power of minus m, m is of.
01:52
So we can say here, m is the unit.
01:58
So here of pure.
02:01
Water so this is of pure water so now coming to the solubility product we should know the molar mass so molar mass of here p b c r o4 is equal to 323 .13 .19 gram per moles so this is the molar mass we know now so, this is in, we can know that pbcro4 in solid state...