00:01
Okay, calculate solubility of the barrier sulfates.
00:05
So the barrier sulfate will actually dissociate into the barium 2 plus and the sulfate iron.
00:26
So from here, if we assume the model solubility is c, right? then we will know in the saturated solution, the concentration the barrier will be c.
00:38
And the concentration of the sulfate will also be c because the ratio is one to one.
00:45
So from here we can write down an expression of the ksp.
00:49
That's equal to the concentration at barion times the concentration of sulfate.
00:59
And that's equal to what? the ksp can be fined, which is 1 .5 times 10 to minus 9.
01:08
And the concentration is actually c, right? so it becomes c squared.
01:13
So the c actually equals to 3 .a .73 times 10 to minus 5 more...