00:01
To calculate the standard cell potential for the following electrochemical cell, we recognize that whatever is written on the left -hand side is the anode, where oxidation occurs, and whatever is written to the right -hand side of the double line is the cathode, where reduction occurs.
00:22
We probably need another electrode here too, but that really won't change the answer.
00:34
So, e cell is standard, is going to be equal to the reduction potential for the cathode, for what's reduced.
00:45
We have pbo2, which is lead 4 oxide, being reduced to lead 2+.
00:56
Lead ends up going from a plus 4 oxidation state to a plus 2 oxidation state.
01:06
That corresponds to the half reaction pbo2 solid plus 4 h +, plus 2 electrons, goes to pb2 +, plus 2 h2o...