Question

Calculate the standard free energy change for the reduction of O2 by NADH. The relevant standard reduction potentials for the two half-reactions are: E°' (V) ½ O2 + 2 H+ + 2 e- → H2O 0.815 NAD+ + H+ + 2 e- → NADH -0.315 The Faraday constant is 96,485 JV-1mol-1. Extra Credit: Is the reaction spontaneous? Where in an organism does this reaction occur? (Hint: this reaction does not occur in a single step.)

Name: calculate the standard free energy change for the reduction of o2 by nadh the relevant standard reduction potentials for the two half reactions are e v 12 o2 2 h 2 e o h2o 0815 nad h 2 e o n 32556
Uploaded: 2023-02-08T07:10:22-08:00
Duration: 4 min 7 s
Channel: Madhur L
Description: calculate the standard free energy change for the reduction of o2 by nadh the relevant standard reduction potentials for the two half reactions are e v 12 o2 2 h 2 e o h2o 0815 nad h 2 e o n 32556

          Calculate the standard free energy change for the reduction of O2 by NADH. The relevant standard reduction potentials for the two half-reactions are:

E°' (V)
½ O2 + 2 H+ + 2 e- → H2O
0.815
NAD+ + H+ + 2 e- → NADH
-0.315

The Faraday constant is 96,485 J*V-1*mol-1.

Extra Credit: Is the reaction spontaneous? Where in an organism does this reaction occur?
(Hint: this reaction does not occur in a single step.)

Added by Josefa R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

02/08/2023

Step 1

315. The Faraday constant is 96,485 Show more…

Show all steps

Thanks for your feedback!

Calculate the standard free energy change for the reduction of O2 by NADH. The relevant standard reduction potentials for the two half-reactions are: E°' (V) ½ O2 + 2 H+ + 2 e- → H2O 0.815 NAD+ + H+ + 2 e- → NADH -0.315 The Faraday constant is 96,485 J*V-1*mol-1. Extra Credit: Is the reaction spontaneous? Where in an organism does this reaction occur? (Hint: this reaction does not occur in a single step.)